Recall denotes the spine of Outer space.

**1. Plan revisited **

The plan I gave yesterday is for a one year course. After discussing with people, I decided on more realistic contents. In this talk, I intend to discuss various definitions of train tracks. This afternoon, folding. The goal is to prove the following theorems.

- All simplicial automorphisms of belong to .
- Outer space is contractible.
- The Dehn functions of and are exponential.
- The Dehn functions of mapping torus is quadratic.
- If , every topological action of (and hence and ) on or factors through .
- If , then every homomorphism has image at most .
- If is a lattice in a higher rank semisimple Lie group, then every homomorphism from to has finite image.

**2. Simplicial automorphisms **

** 2.1. Results **

Theorem 1 (Bridson, Vogtmann 2001)If , all simplicial automorphisms of belong to .

Note this fails for . The spine is the Farey tree for .

Here is a consequence, which also followed from earlier work of Dyer and Formanek. In this respect, behaves like a lattice in a semisimple group (Mostow rigidity).

Theorem 2 (Bridson, Vogtmann 2000)If , is co-Hopfian, i.e. every monomorphism is an inner automorphism.

** 2.2. Idea of proof **

Need to understand the local structure of . We have seen that homotopically, the link of vertex is a wedge of spheres of dimension .

Lemma 3

- If corresponds to a trivalent graph (maximal in the partial ordering),
- If is a rose (minimal in the partial ordering),
- If is neither trivalent nor a rose, then the link of is the simplicial join of two simplicial complexes.
- Links of roses or trivalent graphs are not joins.

Next, one proves that any simplicial automorphism of preserves the topological type of labelling graphs.

** 2.3. Comment **

Frédéric Haglund: what is the automorphism group of the link of a rose.

Answer: I don’t know. If I knew, this would make the last steps in the previous proof easier.

**3. Outer space is contractible **

The spine is the union of the stars of the roses.

** 3.1. The Culler-Vogtmann proof **

Use Morse theory. Construct a height function with only one critical point. Fix basis . Set

At a rose, thought of as a basis of , height is the sum of length of in the word metric defined by .

Whitehead’s algorithm (or rather Higgins and Lyndon) is a generalisation of Nielsen moves. It amounts to changing maximal tree by swapping one edge (Nielsen moves correspond to the case of one edge trees).

Lemma 4 (Higgins, Lyndon)Let and be roses such that . Then there exists a sequence of roses along which height decreases. is obtained from by a Whitehead automorphism.

Proposition 5Let be a basis of . The roses of minimal height are of the form

Then argue by induction. Fix some ordering on roses such that

Show that adding the star of the next rose preserves contractibility.

**4. Dehn functions **

** 4.1. Non positive curvature **

What we just did sounds like Outer space would have nonpositive curvature. This is not a good picture. If one tries to follow this lines of contraction, one does does not get the weak convexity property required by nonpositive curvature.

One can prove that Outer space is not (seem my thesis). This does not rule out a coarser kind of nonpositive curvature. What does really rule it out is nonpolynomial filling function.

** 4.2. Filling and Dehn functions **

Definition 6By filling area of a loop, we mean the minimal area (i.e. number of -cells) of a simplicial disk filling it. The filling function is

Theorem 7 (Gromov, Bridson)In a finitely presented group acting properly and cocompactly on a simplicial complex, has the same growth type as the Dehn function.

Theorem 8 (Bridson, Vogtmann 1995, Handel, Mosher 2010)If , the Dehn functions of and are exponential (both exponential lower bounds and upper bounds).

** 4.3. Proof **

The proof I explain comes from a short recent note by Vogtmann and me, using a crucial idea from Handel and Mosher.

**The square diagram**. We shall use the spine of Auter space. Recall this is the set of marked graphs with minimal cocompact isometric action.

If , embeds in . There is a map in the opposite direction (restrict action of to subgroup ) and pass to minimal invariant subtree (this requires to fix once and for all a subgroup and kills . This gives a commuting square diagram.

There is a nice geometric proof that has an exponential Dehn function (lower bound). One can exhibit an explicit family of words in generators of which are hard to fill. These give loops in whose images in are hard to fill. Push them to and then . This yields loops which are again hard to fill in .